document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237225>Question 237225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> may i know what is the corrrect process for solving this problem?\r<BR>\n" );
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document.write( "the question is:<BR>\n" );
document.write( "20/(3(2x-8)-(-56)/7)\r<BR>\n" );
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document.write( "thank you so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174453 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This one sure looks UGLY, but a lot of problems are just made to LOOK that way--they really are not as bad as they LOOK!!  \r<BR>\n" );
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document.write( "First, divide the fraction (-56)/7 =-8, and remember that -(-8)=+8.\r<BR>\n" );
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document.write( "Next, you have  \r<BR>\n" );
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document.write( "20/(3(2x-8)-(-56)/7)\r<BR>\n" );
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document.write( "20/(3(2x-8+8))\r<BR>\n" );
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document.write( "20/(3(2x))<BR>\n" );
document.write( "20/(6x)\r<BR>\n" );
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document.write( "Divide out a factor of 2:<BR>\n" );
document.write( "10/(3x)\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje </SPAN>\n" );
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