document.write( "Question 236977: I have two trains
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document.write( "Train A leaves moving at 100mph and passes a station at 9:20pm
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document.write( "Train B leaves moving at 125mph and passes the same station at 9:32
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document.write( "what time will train B catch up to train A \n" );
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Algebra.Com's Answer #174450 by innermotive(1) ![]() You can put this solution on YOUR website! Formula is d=r*t \n" ); document.write( "Train A d=100(t+1) \n" ); document.write( "Train B d=125t \n" ); document.write( "Substitue 125t for d \n" ); document.write( "125t=100(t+1) \n" ); document.write( "Multiply to remove parentheses on the right \n" ); document.write( "125t=100t+100 \n" ); document.write( "25t=100 \n" ); document.write( "Divide 100 by 25 = 4 \n" ); document.write( "Answer is 4 hours later or 1:20am\r \n" ); document.write( "\n" ); document.write( "To check the answer: \n" ); document.write( "Find the distance that is traveled \n" ); document.write( "Train B 125*4=500 miles \n" ); document.write( "Train A 4+1*100=500 miles\r \n" ); document.write( "\n" ); document.write( "Both trains travel the same distance\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |