document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237136>Question 237136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the rational and real zeros of 2x^4-x^3-23x^2+10x+30. I have already found -1, and 3/2 to be rational zeros, but I end up with 2x^2-20, and I don't know what to do with it, can you help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174449 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2 - 20 yields two real (but not rational) zeros\r<BR>\n" );
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document.write( "2x^2 - 20 = 0\r<BR>\n" );
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document.write( "x^2 - 10 = 0\r<BR>\n" );
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document.write( "x^2 = 10\r<BR>\n" );
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document.write( "x = ± sqrt(10) </SPAN>\n" );
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