document.write( "Question 237159: an investment advisor invested 12000 into two accounts. one investment earned 7 % annual simple interest and the other investment earned 6.5% annual simple interest. the amount of interest for 1 year was 820. How much was invested at 6.5 % \n" ); document.write( "
Algebra.Com's Answer #174440 by checkley77(12844)\"\" \"About 
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.07X+.065(12,000-X)=820
\n" ); document.write( ".07X+780-.065X=820
\n" ); document.write( ".005X=820-780
\n" ); document.write( ".005X=40
\n" ); document.write( "X=40/.005
\n" ); document.write( "X=8,000 AMOUNT INVESTED @ 7%.
\n" ); document.write( "12,000-8,000=4,000 AMOUNT INVESTED @ 6.5%
\n" ); document.write( "PROOF:
\n" ); document.write( ".07*8,000+.065*4,000=820
\n" ); document.write( "560+260=820
\n" ); document.write( "820=820
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