document.write( "Question 237159: an investment advisor invested 12000 into two accounts. one investment earned 7 % annual simple interest and the other investment earned 6.5% annual simple interest. the amount of interest for 1 year was 820. How much was invested at 6.5 % \n" ); document.write( "
Algebra.Com's Answer #174440 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .07X+.065(12,000-X)=820 \n" ); document.write( ".07X+780-.065X=820 \n" ); document.write( ".005X=820-780 \n" ); document.write( ".005X=40 \n" ); document.write( "X=40/.005 \n" ); document.write( "X=8,000 AMOUNT INVESTED @ 7%. \n" ); document.write( "12,000-8,000=4,000 AMOUNT INVESTED @ 6.5% \n" ); document.write( "PROOF: \n" ); document.write( ".07*8,000+.065*4,000=820 \n" ); document.write( "560+260=820 \n" ); document.write( "820=820 \n" ); document.write( " \n" ); document.write( " |