document.write( "Question 237157: an invested 12000 i two accounts. one investment earned 7 % annual simple interest and the other investment earned 6.5% annual simple interest. the amount of interest for 1 year was 820. How much was invested at 6.5 % \n" ); document.write( "
Algebra.Com's Answer #174411 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! .07x+.065(12000-x)=820 \n" ); document.write( ".07x+780-.065x=820 \n" ); document.write( ".005x=40 \n" ); document.write( "x=$8000 at 7% \n" ); document.write( "$4000 at 6.5% \n" ); document.write( " |