document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30698>Question 30698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am lost with this question. solve by the substitution method, and determine wehter the equation is dependent, independent or inconsistent.\r<BR>\n" );
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document.write( "3x-6y=5<BR>\n" );
document.write( "2y=4x-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17440 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y=4x-6 original equation<BR>\n" );
document.write( "y=2x-3 get 'y' by itself<BR>\n" );
document.write( "plug y in the next equation:<BR>\n" );
document.write( "3x-6y=5<BR>\n" );
document.write( "3x - 6(2x-3)=5<BR>\n" );
document.write( "3x-12x+18=5<BR>\n" );
document.write( "-9x=-13<BR>\n" );
document.write( "x = 13/9<BR>\n" );
document.write( "plug in 'x' for one of the equation(s):<BR>\n" );
document.write( "3x-6y=5<BR>\n" );
document.write( "3(13/9)-6y=5<BR>\n" );
document.write( "13/3 - 6y = 15/3<BR>\n" );
document.write( "(-6y=2/3)(-1/6)<BR>\n" );
document.write( "y = -1/9 </SPAN>\n" );
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