document.write( "Question 237118: I was wondering if in the theorum of a2 + b2 = c2 if you can designate all the values as 1 so that the equation would read 1 squared + 1 squared = 1 squared? If you can not do this, I was wondering if you could explain to me why that is? Thank you! \n" ); document.write( "
Algebra.Com's Answer #174389 by HeyEv(4)\"\" \"About 
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1^2 + 1^2 = 1^2\r
\n" ); document.write( "\n" ); document.write( "it would not work out because 1 squared is 1,
\n" ); document.write( "and 1 plus one equals 2.
\n" ); document.write( "2 doesn't equal one.
\n" ); document.write( "______________________________
\n" ); document.write( "the only way 1 could be close C would be to find the square root of .5 because .5+.5 = 1
\n" ); document.write( "right?
\n" ); document.write( "well the square root of .5 is .7071067812
\n" ); document.write( "if you were to round to .71
\n" ); document.write( "you'd get\r
\n" ); document.write( "\n" ); document.write( ".5041 + .5041 = 1.0082
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