document.write( "Question 237015: An express train and a local train leave Grays Lake at 3:00 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrivies 1 hour ahead of the local. Find the speed of each train algebraically and show work. I believe the speed of the trains is 40 and 20 miles per hour respectivelly.. I'm having trouble formulating the equations
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document.write( "Thanks \n" );
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Algebra.Com's Answer #174349 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An express train and a local train leave Grays Lake at 3:00 P.M. and head for Chicago 50 miles away. The express travels twice as fast as the local and arrivies 1 hour ahead of the local. Find the speed of each train algebraically and show work. I believe the speed of the trains is 40 and 20 miles per hour respectivelly.. I'm having trouble formulating the equations \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "Express train DATA \n" ); document.write( "rate = 2x mph ; distance = 50 miles ; time = d/r = 50/2x hrs \n" ); document.write( "------------------------ \n" ); document.write( "Local train DATA: \n" ); document.write( "rate = x mph ; distance = 50 miles ; time = 50/x hrs \n" ); document.write( "------------------------ \n" ); document.write( "Equation: \n" ); document.write( "local time - express time = 1 hr \n" ); document.write( "50/x - 50/2x = 1 \n" ); document.write( "50/x - 25/x = 1 \n" ); document.write( "Multiply thru by \"x\": \n" ); document.write( "50 - 25 = x \n" ); document.write( "x = 25 mph (speed of the local train) \n" ); document.write( "2x = 50 mph (speed of the express train) \n" ); document.write( "======================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |