document.write( "Question 236977: I have two trains
\n" ); document.write( "Train A leaves moving at 100mph and passes a station at 9:20pm
\n" ); document.write( "Train B leaves moving at 125mph and passes the same station at 9:32
\n" ); document.write( "what time will train B catch up to train A
\n" ); document.write( "

Algebra.Com's Answer #174315 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
100T=125(T-.2)
\n" ); document.write( "100T=125T-25
\n" ); document.write( "100T-125T=-25
\n" ); document.write( "-25T=-25
\n" ); document.write( "T=-25/-25
\n" ); document.write( "T=1 HOUR AFTER TRAIN A LEAVES THEY WILL MEET.
\n" ); document.write( "9:20+1:00=10:20 TIME OF THE MEETING.
\n" ); document.write( "PROOF:
\n" ); document.write( "100*1=125(1-.2)
\n" ); document.write( "100=125*.8
\n" ); document.write( "100=100
\n" ); document.write( "
\n" );