document.write( "Question 236977: I have two trains
\n" );
document.write( "Train A leaves moving at 100mph and passes a station at 9:20pm
\n" );
document.write( "Train B leaves moving at 125mph and passes the same station at 9:32
\n" );
document.write( "what time will train B catch up to train A \n" );
document.write( "
Algebra.Com's Answer #174315 by checkley77(12844) ![]() You can put this solution on YOUR website! 100T=125(T-.2) \n" ); document.write( "100T=125T-25 \n" ); document.write( "100T-125T=-25 \n" ); document.write( "-25T=-25 \n" ); document.write( "T=-25/-25 \n" ); document.write( "T=1 HOUR AFTER TRAIN A LEAVES THEY WILL MEET. \n" ); document.write( "9:20+1:00=10:20 TIME OF THE MEETING. \n" ); document.write( "PROOF: \n" ); document.write( "100*1=125(1-.2) \n" ); document.write( "100=125*.8 \n" ); document.write( "100=100 \n" ); document.write( " |