document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236956>Question 236956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the skid mark of an automobile sliding to a stop is directly proportional to the square of the velocity.  It was found that a car traveling 60 miles per hour left a skid mark 172 feet in length when attempting to stop.  Find the length of the skid marks of a car traveling 50 miles per hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174304 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  L=  skid  length  in  ft,,,,v= veolcity  in  MPH<BR>\n" );
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document.write( "L=kv^2<BR>\n" );
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document.write( "subst  data  given,,,,,172 = k (60)^2,,,,,,,k=  172/60^2 = .0477<BR>\n" );
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document.write( "proportion  becomes,,,L= .0477 v^2<BR>\n" );
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document.write( "for  v=50,,,,,L = .0477 * 50^2 = 119.44  ft<BR>\n" );
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document.write( "checking,,,, 119.44/50^2 = .0477,,,,ok<BR>\n" );
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