document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236958>Question 236958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following motion problems.  Set up an equation and solve.\r<BR>\n" );
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document.write( "A boy rode his bicycle into the country at the rate of 15 miles per hour and returned over the same route at 12 miles per hour.  If he was bicycling for 4.5 hours, how far into the country did he ride?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174298 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174298\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "12T=15(4.5-T)<BR>\n" );
document.write( "12T=67.5-15T<BR>\n" );
document.write( "12T+15T=67.5<BR>\n" );
document.write( "27T=67.5<BR>\n" );
document.write( "T=67.5/27<BR>\n" );
document.write( "T=2.5 HOURS FOR THE 12 MPH. TRIP.<BR>\n" );
document.write( "12*2.5=30 MILES IS THE DISTANCE.<BR>\n" );
document.write( "15(4.5-2.5)=15*2=30 MILES DITTO.\r<BR>\n" );
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