document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236943>Question 236943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the center and radius of the following circle.\r<BR>\n" );
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document.write( "9x2 + 12x + 9y2 - 18y - 23 =0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174285 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the center and radius of the following circle. <BR>\n" );
document.write( "9x2 + 12x + 9y2 - 18y - 23 =0<BR>\n" );
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document.write( "9(x^2 + (4/3)x + (2/3)^2) + 9(y^2 - 2y + 1) = 23 +9(2/3)^2 + 9<BR>\n" );
document.write( "9(x+(2/3))^2 + 9(y-1)^2 = 68<BR>\n" );
document.write( "(x+(2/3)^2 + (y-1)^2 = 68/9<BR>\n" );
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document.write( "Center: (-2/3 , 1)<BR>\n" );
document.write( "Radius: (sqrt(68))/3 = (2/3)sqrt(17)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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