document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236898>Question 236898</A>: <I><SPAN STYLE=\"word-break: break-all;\">  40'x 80' rectangular lot...2 boys mowing one decided that will stop at a uniform distance ..moving using the collapsing pattern....what uniform distance should one stop mowing </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174259 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40*80=3200 area<BR>\n" );
document.write( "3200/2=1600 half area each must mow.<BR>\n" );
document.write( "Let x=the uniform distance from the perimeter.<BR>\n" );
document.write( "(40-x)(80-x)=1600<BR>\n" );
document.write( "3200-120x+x^2=1600<BR>\n" );
document.write( "x^2-120x+1600=0<BR>\n" );
document.write( "x^2-120x+3600=3600-1600 completing the square.<BR>\n" );
document.write( "(x-60)^2=2000<BR>\n" );
document.write( "x-60=+-sqrt(400*5)<BR>\n" );
document.write( "x=60+20sqrt(5)=104' approx (too large) <BR>\n" );
document.write( "x=60-20sqrt(5) ' Answer (15.28' approx)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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