document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236877>Question 236877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> im not sure why i cant pickout the most imporant info in these word problems please help...\r<BR>\n" );
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document.write( "If the length of a rectangle is 1km longer than twice the width then what is the length if the areaa is 55 square kilometer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174239 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  L = Length,,,,,W= Width<BR>\n" );
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document.write( "Area = A =  L*W,,,,,but  L= 2W + 1<BR>\n" );
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document.write( "A= ( 2W+1) (W) = 2w^2 +W,,,,,and  A= 55<BR>\n" );
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document.write( "2W^2 +W - 55 = 0,,,,,factor<BR>\n" );
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document.write( "(2W +11)(W-5) =0 <BR>\n" );
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document.write( "2w+11=0,,,,W=-11/2,,,not  realistic<BR>\n" );
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document.write( "W-5 =0,,,,W=5   and  L= 2*5 +1 =11<BR>\n" );
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document.write( "check,,,,,,LW= 5*11=55,,,,,ok<BR>\n" );
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document.write( "2*5 +1 =11,,,,,,ok<BR>\n" );
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document.write( " </SPAN>\n" );
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