document.write( "Question 236845: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Find k to make the trinomial a perfect square:\r
\n" ); document.write( "\n" ); document.write( "r square + 10r + k\r
\n" ); document.write( "\n" ); document.write( "Thank you, Carrie
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Algebra.Com's Answer #174233 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Remember, perfect squares are of the form \"%28a%2Bb%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "In this case, we want a perfect square of the form \"%28r%2Bx%29%5E2\" where 'x' is an unknown expression or number.\r
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\n" ); document.write( "\n" ); document.write( "\"%28r%2Bx%29%5E2=r%5E2%2B10r%2Bk\" Set that perfect square expression equal to the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2%2B2rx%2Bx%5E2=r%5E2%2B10r%2Bk\" FOIL the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"2rx%2Bx%5E2=10r%2Bk\" Subtract \"r%5E2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Since the only terms with 'r' in them are 2rx and 10r, this means that \"2rx=10r\". Divide both sides by 'r' to get \"2x=10\". Now solve for 'x' to get \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "So the left side of \"%28r%2Bx%29%5E2\" becomes \"%28r%2B5%29%5E2\". FOIL this expression out to get \"%28r%2B5%29%5E2=r%5E2%2B10r%2B25\". So we see that the value of k is k=25.\r
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\n" ); document.write( "\n" ); document.write( "Hopefully you understand this whole process (if not, just ask). Once you do, there is a handy shortcut. The value of 'k' is simply equal to half the coefficient of 'r' squared. In other words,\r
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\n" ); document.write( "\n" ); document.write( "\"k=%2810%2F2%29%5E2=5%5E2=25\" which is what we just got.\r
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