document.write( "Question 236805: The length of a rectangle is 10 m less than twice the width of the rectangle. The area is 2800 m2. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #174217 by checkley77(12844) ![]() You can put this solution on YOUR website! L=2W-10 \n" ); document.write( "AREA=LW \n" ); document.write( "2,800=(2W-10)W \n" ); document.write( "2,800=2W^2-10W \n" ); document.write( "2W^2-10W-2,800=0 \n" ); document.write( "2(W^2-5W-1,400)=0 \n" ); document.write( "2(W-40)(W+30)=0 \n" ); document.write( "W-40=0 \n" ); document.write( "W=40 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*40-10 \n" ); document.write( "L=80-10 \n" ); document.write( "L=70 ANS. FOR THE LENGTH. \n" ); document.write( "pROOF: \n" ); document.write( "2,800=40*70 \n" ); document.write( "2,800=2,800 \n" ); document.write( " |