document.write( "Question 236805: The length of a rectangle is 10 m less than twice the width of the rectangle. The area is 2800 m2. Find the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #174217 by checkley77(12844)\"\" \"About 
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L=2W-10
\n" ); document.write( "AREA=LW
\n" ); document.write( "2,800=(2W-10)W
\n" ); document.write( "2,800=2W^2-10W
\n" ); document.write( "2W^2-10W-2,800=0
\n" ); document.write( "2(W^2-5W-1,400)=0
\n" ); document.write( "2(W-40)(W+30)=0
\n" ); document.write( "W-40=0
\n" ); document.write( "W=40 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*40-10
\n" ); document.write( "L=80-10
\n" ); document.write( "L=70 ANS. FOR THE LENGTH.
\n" ); document.write( "pROOF:
\n" ); document.write( "2,800=40*70
\n" ); document.write( "2,800=2,800
\n" ); document.write( "
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