document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236838>Question 236838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> algebra inverse function question\r<BR>\n" );
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document.write( "how do I solve 2x+1/x-1 for the inverse when I can't get y by itself when I replace all of the x's with y's to find the inverse?<BR>\n" );
document.write( "help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174213 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=(2x+1)/(x-1)<BR>\n" );
document.write( "y=( 2x+1)/(x-1)<BR>\n" );
document.write( "y(x-1)=2x+1 Now we solve for x.<BR>\n" );
document.write( "xy-y=2x+1<BR>\n" );
document.write( "xy-2x=y+1 Get the x's on one side.<BR>\n" );
document.write( "x(y-2)=y+1<BR>\n" );
document.write( "x=(y+1)/(y-2)<BR>\n" );
document.write( "y=(x+1)/(x-2) Switch x and y<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%5E%28-1%29%28x%29=%28x%2B1%29%2F%28x-2%29 ALIGN=MIDDLE  ALT=\"f%5E%28-1%29%28x%29=%28x%2B1%29%2F%28x-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > the inverse.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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