document.write( "Question 236833: A man is 20 yrs older than his son.In 10 yrs, he will be twice as old as his will be then be.How old is each?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #174210 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Son=x \n" ); document.write( "Dad=x+20 \n" ); document.write( "(x+20)+10=2(x+10) \n" ); document.write( "x+30=2x=20 \n" ); document.write( "x-2x=20-30 \n" ); document.write( "-x=-10 \n" ); document.write( "x=10 age of the son now. \n" ); document.write( "10+20=30 age of the dad now. \n" ); document.write( "Proof: \n" ); document.write( "(10+20)+10=2(10+10) \n" ); document.write( "30+10=2*20 \n" ); document.write( "40=40 \n" ); document.write( " |