document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30696>Question 30696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne wants to create a mix of two coffees, one is $8.40 a lb. and the other is $7.28 a lb.  How many pounds of the $7.28 coffess should she ad to 9 pounds of the $8.40 coffee to sell the mixture for $7.95 a pound?  I had a problem like this last week,  i did not get my homework back to use as a reference...please help, I'm lost after....$8.40 x 9 = $75.60. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17420 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LEt the solution be x<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "7.28x+8.4(9)=7.95(x+8)<BR>\n" );
document.write( "7.28x+75.6=63.6+7.95x<BR>\n" );
document.write( "0.67x=12<BR>\n" );
document.write( "x=17.9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence, about 17.9 pounds of solution must be added.<BR>\n" );
document.write( "PAul. </SPAN>\n" );
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