document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30699>Question 30699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two planes leave at the same time and head in opposite directions.  One travels 80mph faster than the other.  After 3 hours, they are 2,940 miles apart.  What is the rate of each plane?  Plane  DISABLED_event_one=  b + 80 and plane two = b.   The rest of this is not calculating for me.  I know that the three hours figure in there somehow yet can't figure where.  Please help me.  Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17418 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Speed of first palne = x<BR>\n" );
document.write( "Speed of second plane = x+80<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "3(x+x+80)=2940<BR>\n" );
document.write( "6x+240=2940<BR>\n" );
document.write( "6x=2700<BR>\n" );
document.write( "x=450\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "450+80=530\r<BR>\n" );
document.write( "\n" );
document.write( "Hence, the speed of one plane is 430mph and speed of another is 530mph.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );