document.write( "Question 236706: Vince left trout creek driving at 40km/h. Sybil followed 2h later driving at 50km/h. How far down the road will Sybil overtake Vince?\r
\n" ); document.write( "\n" ); document.write( "Also to solve it, it must either be the substitution or elimination method.\r
\n" ); document.write( "\n" ); document.write( "Thanks. \n" ); document.write( "
Algebra.Com's Answer #174169 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Vince left trout creek driving at 40km/h. Sybil followed 2h later driving at 50km/h. How far down the road will Sybil overtake Vince?
\n" ); document.write( "Also to solve it, it must either be the substitution or elimination method.
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\n" ); document.write( "Vince DATA:
\n" ); document.write( "rate = 40 km/h ; distance = v km ; time = d/r = v/40 hrs.
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\n" ); document.write( "Sybil DATA:
\n" ); document.write( "rate = 50 km/h ; distance = s km ; time = d/r = s/50 hrs.
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\n" ); document.write( "Equations:
\n" ); document.write( "vince time - sybil time = 2 hrs
\n" ); document.write( "v/40 - s/50 = 2
\n" ); document.write( "---
\n" ); document.write( "vince distance = sybil distance
\n" ); document.write( "v = s
\n" ); document.write( "----------------------------
\n" ); document.write( "Substitute for \"v\" and solve for \"s\":
\n" ); document.write( "s/40 -s/50 = 2
\n" ); document.write( "50s - 40s = 2*40*50
\n" ); document.write( "10s = 80*50
\n" ); document.write( "s = 400 km (distance sybil will have to drive to overtake vince)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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