document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236571>Question 236571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During the first part of a trip, a canoeist travels 79 miles at a certain speed. The canoeist travels 2 miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 2 hrs. What was the speed on each part of the trip? (Simplify the answer, type an integer or a decimal point, round to the nearest hundredth). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174119 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (79/v)+2/(v-5)=2\r<BR>\n" );
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document.write( "Multiply out gives\r<BR>\n" );
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document.write( "(79v-395+2v)/v^2-5v = 2\r<BR>\n" );
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document.write( "81v-395 = 2v^2-10V\r<BR>\n" );
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document.write( "-395 = 2v^2-91v\r<BR>\n" );
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document.write( "divide each side by 2\r<BR>\n" );
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document.write( "-395/2 = v^2-91v/2\r<BR>\n" );
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document.write( "Complete the square\r<BR>\n" );
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document.write( "-395/2 = (v-91/4)^2 - (91/4)^2\r<BR>\n" );
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document.write( "(-395/2 + (91/4)^2)^1/2 = v - 91/4\r<BR>\n" );
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document.write( "v = 17.89 + 91/4 = 40.64\r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "v = -17.89 + 91/4 = 4.86\r<BR>\n" );
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document.write( "since you can not have a negative speed (4.86 - 5) then we can ignore the second solution for v.\r<BR>\n" );
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document.write( "so the speed on the first part of the trip was 40.64 mph and 35.64mph on the second part. </SPAN>\n" );
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