document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236564>Question 236564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much does an alloy that is 20% copper should be mixed with 200 onces of an alloy that is 90% copper in order to get an alloy that is 30% copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174101 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much does an alloy that is 20% copper should be mixed with 200 onces of an alloy that is 90% copper in order to get an alloy that is 30% copper<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "copper + copper = copper<BR>\n" );
document.write( "0.20x + 0.90*200 = 0.30(x+200)<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "20x + 90*200 = 30x + 30*200<BR>\n" );
document.write( "-10x = -60*200<BR>\n" );
document.write( "x = 1200 onces (amt of 20% alloy needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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