document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30684>Question 30684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the speed of a boat in still water is 24 miles per hour. if the boat travels 54 miles upstream in the same time it takes to travel 90 miles downstream, what is the rate of the stream? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17410 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 54/(24-C)=90/(24+C) CROSS MULTIPLYING GIVES 1296+54C=2160-90C OR 144C=864 OR\r<BR>\n" );
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document.write( "C=6 THEREFORE THE CURRENT IS 6MPH\r<BR>\n" );
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document.write( "PROOF 54/(24-6)=90/(24+6) OR 54/18=90/30 PR 3=3  </SPAN>\n" );
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