document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236522>Question 236522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this ((( 1/2ln(x+3)-lnx=0 ))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174089 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2ln(x+3)-lnx=0\r<BR>\n" );
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document.write( "ln((x+3)^(1/2))-ln(x)=0\r<BR>\n" );
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document.write( "ln(sqrt(x+3))-ln(x)=0\r<BR>\n" );
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document.write( "ln(sqrt(x+3)/x)=0\r<BR>\n" );
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document.write( "sqrt(x+3)/x=1\r<BR>\n" );
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document.write( "sqrt(x+3)=x\r<BR>\n" );
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document.write( "x+3=x^2\r<BR>\n" );
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document.write( "x^2-x-3=0\r<BR>\n" );
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document.write( "x=1/2+(1/2)*sqrt(13) or x=1/2-(1/2)*sqrt(13)\r<BR>\n" );
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document.write( "Answer: Only solution is x = 1/2+(1/2)*sqrt(13) (other is extraneous) </SPAN>\n" );
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