document.write( "Question 236505: find the solution(s) of the equation?
\n" ); document.write( "log(x-1)-log(x+6)=log(x-2)-log(x-3) \n" ); document.write( "

Algebra.Com's Answer #174083 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( " $\"log%28%28x-1%29%29-log%28%28x%2B6%29%29+=+log%28%28x-2%29%29-log%28%28x-3%29%29\"$ Apply the quotient rule for logarithms: $\"log%28%28M%29%29-log%28%28N%29%29+=+log%28%28M%2FN%29%29\"$
\n" ); document.write( " $\"log%28%28%28x-1%29%2F%28x%2B6%29%29%29+=+log%28%28%28x-2%29%2F%28x-3%29%29%29\"$ If $\"log%28%28M%29%29+=+log%28%28N%29%29\"$ then $\"M+=+N\"$
\n" ); document.write( " $\"%28x-1%29%2F%28x%2B6%29+=+%28x-2%29%2F%28x-3%29\"$ Cross-multiply.
\n" ); document.write( " $\"%28x-1%29%28x-3%29+=+%28x-2%29%28x%2B6%29\"$ Perform the indicated multiplication.
\n" ); document.write( " $\"x%5E2-4x%2B3+=+x%5E2%2B4x-12\"$ Subtract $\"x%5E2\"$ from both sides.
\n" ); document.write( " $\"-4x%2B3+=+4x-12\"$ Add 4x to both sides.
\n" ); document.write( " $\"3+=+8x-12\"$ Add 12 to both sides.
\n" ); document.write( " $\"15+=+8x\"$ Divide both sides by 8.
\n" ); document.write( " $\"x+=+15%2F8\"$
\n" ); document.write( " $\"highlight%28x+=+1.875%29\"$ \n" ); document.write( "

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