document.write( "Question 236458: I need help solving this word problem please:\r
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document.write( "A rectangle is 4 cm longer than it is wide. If the length and width are both decreased by 2 cm, the area is decreased by 24 cm2 (I'm trying to type cm squared). Find the dimensions of the original rectangle. \r
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document.write( "Thank you so very much for your help on this math homework problem. \n" );
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Algebra.Com's Answer #174042 by JimboP1977(311)![]() ![]() You can put this solution on YOUR website! Well you have a rectangle of length x + 4cm multiplied by x:\r \n" ); document.write( "\n" ); document.write( "(x+4)*x = x^2+4x (this is the original area of the rectangle)\r \n" ); document.write( "\n" ); document.write( "The length and width are reduced by 2cm so:\r \n" ); document.write( "\n" ); document.write( "(x+2)(x-2) = x^2+4 (this is the new area of the rectangle)\r \n" ); document.write( "\n" ); document.write( "So the original area of the rectangle is decreased by 24cm^2 so:\r \n" ); document.write( "\n" ); document.write( "x^2-4 = x^2+4x-24\r \n" ); document.write( "\n" ); document.write( "Rearrange to find x gives:\r \n" ); document.write( "\n" ); document.write( "-4 = 4x-24\r \n" ); document.write( "\n" ); document.write( "x = 20/4\r \n" ); document.write( "\n" ); document.write( "x = 5\r \n" ); document.write( "\n" ); document.write( "So dimensions of the original rectangle are 9cm by 5cm.\r \n" ); document.write( "\n" ); document.write( "To double check we do 9*5 = 45 cm^2 \n" ); document.write( " 7*3 = 21 cm^2 \n" ); document.write( " \n" ); document.write( "Difference of 24cm^2\r \n" ); document.write( "\n" ); document.write( "Does this make sense? \n" ); document.write( " |