document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236455>Question 236455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8-y/2-y=y-8/y-2  I know these are equal. But why??? I have to prove why they are equal. I was thinking maybe if I multiply them by their inverses then they would both equal 1. Please help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174034 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply each side by its denominator to give:\r<BR>\n" );
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document.write( "(8-y)(y-2) = (y-8)(2-y)\r<BR>\n" );
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document.write( "Multiplying the brackets gives:\r<BR>\n" );
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document.write( "8y-16-y^2+2y = 2y-y^2-16+8y\r<BR>\n" );
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document.write( "-y^2+10y-16 = -y^2+10y-16<BR>\n" );
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