document.write( "Question 236369: You travel north 5 miles then south 3 mile in the same amount of time. Your speed going south was 6 mph than going north. Find the speed each way and the amount of time spent going each direction. \n" ); document.write( "
Algebra.Com's Answer #173996 by JimboP1977(311)![]() ![]() You can put this solution on YOUR website! We use the equation distance/time = speed. Rearranged is distance/speed = time.\r \n" ); document.write( "\n" ); document.write( "D/S = T\r \n" ); document.write( "\n" ); document.write( "We travelled north 5 miles in speed that is 6 mph more than we travelled south. So we can say:\r \n" ); document.write( "\n" ); document.write( "5/(x+6) \r \n" ); document.write( "\n" ); document.write( "Where x is the unknown speed.\r \n" ); document.write( "\n" ); document.write( "We travelled south at x speed:\r \n" ); document.write( "\n" ); document.write( "3/x\r \n" ); document.write( "\n" ); document.write( "Now because we know that the time taken to travel these two distance was the same we can say these two equations equal each other:\r \n" ); document.write( "\n" ); document.write( "5/(x+6) = 3/x\r \n" ); document.write( "\n" ); document.write( "So we need to rearrange to get x on its own:\r \n" ); document.write( "\n" ); document.write( "5x/(x+6) = 3\r \n" ); document.write( "\n" ); document.write( "5x = 3x+18\r \n" ); document.write( "\n" ); document.write( "2x = 18\r \n" ); document.write( "\n" ); document.write( "x = 9\r \n" ); document.write( "\n" ); document.write( "So the speed going north was 15 mph, speed going south was 9mph. Time going north was 5 miles divided by 15 mph = 1/3 hour or 20 minutes which is the same time going south.\r \n" ); document.write( "\n" ); document.write( "Does that help?\r \n" ); document.write( "\n" ); document.write( "Make any sense? \n" ); document.write( " |