document.write( "Question 236340: What is the smallest integer that could be part of a set of two or more positive consecutive integers whose sum is 100?
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Algebra.Com's Answer #173988 by Theo(13342) You can put this solution on YOUR website! I believe the number is 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 sum 9 \n" ); document.write( "10 sum 19 \n" ); document.write( "11 sum 30 \n" ); document.write( "12 sum 42 \n" ); document.write( "13 sum 55 \n" ); document.write( "14 sum 69 \n" ); document.write( "15 sum 84 \n" ); document.write( "16 sum 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I summed the numbers from 1 up to when i got past 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I then looked at each number over 100 to see if there were sums in the lower range of numbers that I could subtract to get 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When I got to the sum of the number at 16 was 136, I saw that the sum of the numbers at 8 totaled 36 so I could subtract the first 8 numbers from the set and my total from 9 to 16 would equal 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It worked although I don't have a formula to apply to it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The formula for the sum of an arithmetic progression can be applied.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = n*(x+y)/2 where\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = first number in the sequence \n" ); document.write( "y = last number in the sequence.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For this progression, we have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 8 \n" ); document.write( "x = 9 \n" ); document.write( "y = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 8*(9+16)/2 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 8*25/2 = 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Our solution became:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 16*(1+16)/2 - 8*(1+8)/2 which became:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S = 8*17 - 4*9 = 136 - 36 = 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I suspect there's a generic formula in there to help solve this problem a little more rigorously using algebra, but I don't have that answer for you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer, however, is correct as best as I can determine, and it is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The smallest number in a consecutive series that adds up to 100 is 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The number of numbers involved is 8.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |