document.write( "Question 236035: can you help me factor \r
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Algebra.Com's Answer #173985 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
4x^3+4x^2y-24xy^2\r
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\n" ); document.write( "\n" ); document.write( "factor out 4x to get:\r
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\n" ); document.write( "\n" ); document.write( "4x * (x^2 + xy - 6y^2)\r
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\n" ); document.write( "\n" ); document.write( "if you didn't have the y there, your equation within the parentheses would have been:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + x - 6 which factors as (x+3) * x-2)\r
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\n" ); document.write( "\n" ); document.write( "if you add a y into the right side of each of the factors, you get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + xy - 6y^2 = (x+3y) * (x-2y)\r
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\n" ); document.write( "\n" ); document.write( "this looks like it will actually work.\r
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\n" ); document.write( "\n" ); document.write( "your factors should be:\r
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\n" ); document.write( "\n" ); document.write( "4x * (x+3y) * (x-2y)\r
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\n" ); document.write( "\n" ); document.write( "to confirm they are good, work back to see if you can get the original equation again.\r
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\n" ); document.write( "\n" ); document.write( "(x + 3y) * (x-2y) becomes:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 2xy + 3xy - 6y^2 which becomes\r
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\n" ); document.write( "\n" ); document.write( "x^2 + xy - 6y^2\r
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\n" ); document.write( "\n" ); document.write( "multiply that by 4x to get:\r
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\n" ); document.write( "\n" ); document.write( "4x * (x^2 + xy - 6y^2) becomes:\r
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\n" ); document.write( "\n" ); document.write( "4x^3 + 4x^2y - 24xy^2\r
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\n" ); document.write( "\n" ); document.write( "your original equation is:\r
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\n" ); document.write( "\n" ); document.write( "4x^3 + 4x^2y - 24xy^2\r
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\n" ); document.write( "\n" ); document.write( "since they're the same, your answer is confirmed.\r
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\n" ); document.write( "\n" ); document.write( "your answer is:\r
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\n" ); document.write( "\n" ); document.write( "4x * (x+3y) * (x-2y)
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