document.write( "Question 236327: solve the quadratic equation by using the square root property.
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Algebra.Com's Answer #173982 by Theo(13342)\"\" \"About 
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4*(a-5)^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "(a-5)^2 = 1/4\r
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\n" ); document.write( "\n" ); document.write( "take square root of both sides to get\r
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\n" ); document.write( "\n" ); document.write( "a-5 = +/- sqrt(1/4)\r
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\n" ); document.write( "\n" ); document.write( "add 5 to both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "a = 5 +/- sqrt(1/4)\r
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\n" ); document.write( "\n" ); document.write( "since sqrt(1/4) = (1/2), equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "a = 5 +/- (1/2)\r
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\n" ); document.write( "\n" ); document.write( "this means:\r
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\n" ); document.write( "\n" ); document.write( "a = 5.5
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\n" ); document.write( "a = 4.5\r
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\n" ); document.write( "\n" ); document.write( "substitute in original equation to confirm this is good.\r
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\n" ); document.write( "\n" ); document.write( "4*(a-5)^2 = 1\r
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\n" ); document.write( "\n" ); document.write( "if a = 4.5, this becomes 4*(-.5)^2 = 1 which becomes 4*(.25) = 1 which becomes 1 = 1 which is good.\r
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\n" ); document.write( "\n" ); document.write( "if a = 5.5, this becomes 4*(.5)^2 = 1 which becomes 4*(.25) = 1 which becomes 1 = 1 which is also good.\r
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\n" ); document.write( "\n" ); document.write( "answer is confirmed.\r
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\n" ); document.write( "\n" ); document.write( "answer is:\r
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\n" ); document.write( "\n" ); document.write( "x = 4.5
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\n" ); document.write( "x = 5.5\r
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