document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236077>Question 236077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the wavelength(W) of a radio wave varies inversely as its frequency(F). A wave with a frequency of 200kHz has a length of 252m. What is the length of a wave with a frequency of 900kHz? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173961 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the wavelength(W) of a radio wave varies inversely as its frequency(F). A wave with a frequency of 200kHz has a length of 252m. What is the length of a wave with a frequency of 900kHz?<BR>\n" );
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document.write( "200*252 = k (a constant)<BR>\n" );
document.write( "L*900 = k = 50400<BR>\n" );
document.write( "L = 50400/900 = 56 meters<BR>\n" );
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document.write( "That's the answer given the data, but it's not correct.  <BR>\n" );
document.write( "The wavelength in meters is 300/f, f = frequency in Megahertz.<BR>\n" );
document.write( "200 KHz = 0.2 MHz<BR>\n" );
document.write( "300/0.2 = 1500 meters, <BR>\n" );
document.write( "not 252 meters </SPAN>\n" );
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