document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236229>Question 236229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An arrow is fired into the air with an initial valocity of 96ft/sec. The hieght of the arrow t seconds after it was shot into the air is given by s(t)=-16t^2 +96t. When should the arrow reach its greatest hieght. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173912 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s(t)=-16t^2 +96t<BR>\n" );
document.write( "At the vertex, when t = -b/2a<BR>\n" );
document.write( "t = -96/-32 = 3 seconds (time at max height)<BR>\n" );
document.write( "t = 3<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "s(3) = -16*9 + 96*3<BR>\n" );
document.write( "s(3) = 144 feet max </SPAN>\n" );
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