document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236182>Question 236182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Merchant mixes tea that sells for $7.20/kg and tea that sells for $9.20/kg to make 100 kg of tea that he sells for $8.80/kg. How many kilograms of each type of tea did he mix?\r<BR>\n" );
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document.write( "Also to solve it, it has to be either the substitution or elimination method. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173899 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=100 OR X=100-Y<BR>\n" );
document.write( "7.20X+9.20Y=8.80*100 NOW REPLACE X IN THISD EQUATION BY (100-Y) & SOLVE FOR X.<BR>\n" );
document.write( "7.20(100-Y)+9.20Y=880<BR>\n" );
document.write( "720-7.20Y+9.20Y=880<BR>\n" );
document.write( "2Y=880-720<BR>\n" );
document.write( "2Y=160<BR>\n" );
document.write( "Y=160/2<BR>\n" );
document.write( "Y=80 POUNDS OF THE $9.20 TEA IS USED.<BR>\n" );
document.write( "X+80=100<BR>\n" );
document.write( "X=100-80<BR>\n" );
document.write( "X=20 POUNDS OF THW $7.20 TEA IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "7.20*20+9.20*80=880<BR>\n" );
document.write( "144+736=880<BR>\n" );
document.write( "880=880<BR>\n" );
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