document.write( "Question 236200: Doris invested some money at 7% and some at 8%. She invested $6000 more at 8% then at 7%. Her total yearly interest from both investments was $1080, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #173884 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .08(x+6,000)+.07x=1,080 \n" ); document.write( ".08x+480+.07x=1,080 \n" ); document.write( ".15x=1,080-480 \n" ); document.write( ".15x=600 \n" ); document.write( "x=600/.15 \n" ); document.write( "x=4,000 amount invested @ 7%. \n" ); document.write( "4,000+6,000=10,000 invested @ 8%. \n" ); document.write( "Proof: \n" ); document.write( ".08*10,000+.07*4,000=1,080 \n" ); document.write( "800+280=1,080 \n" ); document.write( "1,080=1,080 \n" ); document.write( " |