document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=234960>Question 234960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 7:00a.m. Joe starts jogging at 6mi/h. At 7:10a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30a.m.?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173882 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> at 7:00a.m. Joe starts jogging at 6mi/h. At 7:10a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30a.m.? <BR>\n" );
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document.write( "10 min = 1/6 hour<BR>\n" );
document.write( "Joe goes 1 mile in 1/6 hour - he's one mile ahead.<BR>\n" );
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document.write( "To overtake him in 20 minutes (1/3 hour) Ken has to go 3 mph faster (1 mile in 1/3 hour = 3 mph)<BR>\n" );
document.write( "Ken has to go 9 mph<BR>\n" );
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