document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236048>Question 236048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many kilograms of water must be added to 10 kg of a 75% antifreeze solution in order to produce a 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173803 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  how many kilograms of water must be added to 10 kg of a 75% antifreeze solution in order to produce a 50% solution?<BR>\n" );
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document.write( "Let \"x\" be the amount of water added.<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.75(10) + 0(x) = 0.50(10+x)<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "75*10 = 50*10 + 50x<BR>\n" );
document.write( "50x = 25*10<BR>\n" );
document.write( "x = 5 kg (amount of water needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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