document.write( "Question 30642: I need to know the vertex and how to graph it. Thank you.
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document.write( "y=-2(x-3)(x+1) \n" );
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Algebra.Com's Answer #17380 by Fermat(136)![]() ![]() You can put this solution on YOUR website! A parabola which has its vertex at the point (a,b) can be written as, \n" ); document.write( "(y-b) = (x-a)² \n" ); document.write( "or, \n" ); document.write( "(y-b) = C(x-a)² \n" ); document.write( "if it is scaled. \n" ); document.write( "You have y=-2(x-3)(x+1), so convert it to the above form. \n" ); document.write( "y=-2(x-3)(x+1) \n" ); document.write( "expand it, \n" ); document.write( "y = -2(x² - 2x - 3) \n" ); document.write( "y = -2(x² - 2x + 1 - 4) \n" ); document.write( "y = -2{(x - 1)² - 4} \n" ); document.write( "y = -2(x-1)² + 8 \n" ); document.write( "(y-8) = -2(x-1)² \n" ); document.write( "================ \n" ); document.write( "Here the parabola has a scaling factor, 2, which means it is slimmer, and it has a change of sign, the minus sign, hence it is upside down. \n" ); document.write( "The vertex is at the point (a,b) = (1,8) \n" ); document.write( "======================================== \n" ); document.write( " |