document.write( "Question 235944: A is 9 years younger than B,and 6 years older than C; three fourth's of A's age, four fifth's of B's and one half of C's amount with 37 years. find their ages \n" ); document.write( "
Algebra.Com's Answer #173794 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Write an equation for each statement, rewrite the equations to get it in terms of A
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\n" ); document.write( "A is 9 years younger than B,
\n" ); document.write( "A = B-9
\n" ); document.write( "B = A+9
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\n" ); document.write( "and 6 years older than C;
\n" ); document.write( "A = C+6
\n" ); document.write( "C = A-6
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\n" ); document.write( " three fourth's of A's age, four fifth's of B's and one half of C's amount to 37 years.
\n" ); document.write( ".75A + .8B + .5c = 37
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\n" ); document.write( "Replace B & C from the 1st two equations
\n" ); document.write( ".75A + .8(A+9) + .5(A-6) = 37
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\n" ); document.write( ".75A + .8A + 7.2 + .5A - 3 = 37
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\n" ); document.write( ".75A + .8A + .5A + 7.2 - 3 = 37
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\n" ); document.write( "2.05A + 4.2 = 37
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\n" ); document.write( "2.05A = 37 - 4.2
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\n" ); document.write( "2.05A = 32.8
\n" ); document.write( "A = \"32.8%2F2.05\"
\n" ); document.write( "A = 16 yrs old
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\n" ); document.write( "I'll let you find the ages of B & C, check your solutions in the last equation\r
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