document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236010>Question 236010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of 70% antifreeze solution must be mixed with 60 gallons of 10% antifreeze to get a mixture that is 60% antifreeze </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173793 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .70x+.10*60=.60(x+60)<BR>\n" );
document.write( ".70x+6=.60x+36<BR>\n" );
document.write( ".70x-.60x=36-6<BR>\n" );
document.write( ".10x=30<BR>\n" );
document.write( "x=30/.10<BR>\n" );
document.write( "x=300 gal. of 70% anti freeze is used.<BR>\n" );
document.write( "Proof;<BR>\n" );
document.write( ".70*300+.10*60=.60*(300+60)<BR>\n" );
document.write( "210+6=.60*360<BR>\n" );
document.write( "216=216<BR>\n" );
document.write( " </SPAN>\n" );
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