document.write( "Question 236016: How can 54,000 be invested, part at 8% annual simple interest and the remainder at 10%annual simple interest, so that the interest earned by the two accounts will be equal \n" ); document.write( "
Algebra.Com's Answer #173790 by checkley77(12844)\"\" \"About 
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.10X=.08(54,000-X)
\n" ); document.write( ".10X=43.20-.08X
\n" ); document.write( ".10X+.08X=4320
\n" ); document.write( ".18X=4320
\n" ); document.write( "X=4320/.18
\n" ); document.write( "X=24,000 AMOUNRT INVESTED @ 10%.
\n" ); document.write( "54,000-24,000=30,000 AMOUNT INVESTED @ 8%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*24,000=30,000*.08
\n" ); document.write( "2,400=2,400
\n" ); document.write( "
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