document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=236027>Question 236027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the annual rate of growth on an account that was worth $1000 in 1996 and was worth $1400 in 1999.\r<BR>\n" );
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document.write( "I have tried like this: 1996-1999 is 3 years, and it had raised $400<BR>\n" );
document.write( "400/1000 x 100= 40% which means it has raised 40% in 3 years, so is the answer 40/3= 13.33% per year????<BR>\n" );
document.write( "Please tell me if i'm right or wrong. Thanks very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173780 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> well...the problem is, there is growth on growth\r<BR>\n" );
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document.write( "try this ___ 1400 = 1000 (1 + r)^3 </SPAN>\n" );
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