document.write( "Question 235976: A chemist wants to create 60 grams of an nickel alloy that is 65% pure. She has one mixture of an nickel alloy that is 45% pure and another mixture that is 75% pure. How much of each mixture must she use?
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Algebra.Com's Answer #173771 by josmiceli(19441)\"\" \"About 
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Let \"a\" = grams of 45% mixture to be used
\n" ); document.write( "Let \"b\" = grams of 75% mixture to be used
\n" ); document.write( "given:
\n" ); document.write( "(1) \"a+%2B+b+=+60\" grams
\n" ); document.write( "(2) \".45a+%2B+.75b\" = pure nickel in final mixture
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\n" ); document.write( "In words:
\n" ); document.write( "( grams of pure nickel in final mixture )/(total grams) = 65%
\n" ); document.write( "\"%28.45a+%2B+.75b%29+%2F+60+=+.65\"
\n" ); document.write( "\".45a+%2B+.75b+=+39\"
\n" ); document.write( "(3)\"45a+%2B+75b+=+3900\"
\n" ); document.write( "Multiply both sides of (1) by \"45\" and subtract
\n" ); document.write( "(1) from (3)
\n" ); document.write( "(3)\"45a+%2B+75b+=+3900\"
\n" ); document.write( "(1)\"-45a+-+45b+=+-2700\"
\n" ); document.write( "\"30b+=+1200\"
\n" ); document.write( "\"b+=+40\"
\n" ); document.write( "And, since
\n" ); document.write( "\"a+%2B+b+=+60\"
\n" ); document.write( "\"a+%2B+40+=+60\"
\n" ); document.write( "\"a+=+20\"
\n" ); document.write( "20 grams of the 45% mixture and 40 grams of the 75% mixture are needed
\n" ); document.write( "check:
\n" ); document.write( "\"%28.45a+%2B+.75b%29+%2F+60+=+.65\"
\n" ); document.write( "\"%28.45%2A20+%2B+.75%2A40%29+%2F+60+=+.65\"
\n" ); document.write( "\"%28+9+%2B+30%29+%2F+60+=+.65\"
\n" ); document.write( "\"39+=+.65%2A60\"
\n" ); document.write( "\"39+=+39\"
\n" ); document.write( "OK
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