document.write( "Question 30207: when a question asks you to show something algebraically, DO NOT substitute numbers for the variables and give me an example. On the other hand, when a question asks you to show something numerically or to provide an example, you may substitute numbers for the variables. Show all work.\r
\n" ); document.write( "\n" ); document.write( "Solve for t: 2t(sin(t2+1) + cos(t2+1))2 - 4tsin(t2+1)cos(t2+1) = 2. (Hint: remember that [sin(x)]2 is usually written sin2(x); now look for a trigonometric identity.) \n" ); document.write( "
Algebra.Com's Answer #17376 by sdmmadam@yahoo.com(530)\"\" \"About 
You can put this solution on YOUR website!
Solve for t: 2t(sin(t2+1) + cos(t2+1))2 - 4tsin(t2+1)cos(t2+1) = 2.
\n" ); document.write( "2t[sin(t^2+1) + cos(t^2+1)]^2 - 4tsin(t^2+1)cos(t^2+1) = 2. ----(1)
\n" ); document.write( "Put (t^2+1) = y
\n" ); document.write( "2t(siny + cosy)^2 - 4tsinycosy = 2.
\n" ); document.write( "t[(siny + cosy)^2 - 2sinycosy] = 2.
\n" ); document.write( "t[(sin^2y+cos^2y +2sinycosy)- 2sinycosy] = 12
\n" ); document.write( "(using (a+b)^2 = a^2+b^2+2ab where here a =suny and b = cosy )
\n" ); document.write( "t[(sin^2y+cos^2y) +(2sinycosy- 2sinycosy)] = 2 ----(*)
\n" ); document.write( "(by formula sin^2y+cos^2y = 1 )
\n" ); document.write( "t[(1)+0] = 2
\n" ); document.write( "tX(1) = 2
\n" ); document.write( "That is t = 2
\n" ); document.write( "Answer: t = 2
\n" ); document.write( "Remark: If you are wondering about the quantity y or for that matter (t^2+1), the terms in that quantity being of equal in magnitude and opposite in sign have got cancelled by the additive inverse law! as you can see in step (*) \r
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