document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235960>Question 235960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find an angle such that 3 times the complement of the angle is 50 degrees greater than the supplement of the angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173729 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find an angle such that 3 times the complement of the angle is 50 degrees greater than the supplement of the angle?<BR>\n" );
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document.write( "Let the angle be \"x\".<BR>\n" );
document.write( "The complement is \"90-x\"<BR>\n" );
document.write( "The supplement is \"180-x\"<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3(90-x) = 180-x + 50<BR>\n" );
document.write( "270 - 3x = 230 -x<BR>\n" );
document.write( "2x = 40<BR>\n" );
document.write( "x = 20 degrees (the angle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );