document.write( "Question 235950: you can ride a bicycle 15 mph. your sister rides 12 mph. you give her a one hour head start. in how many hours will you catch up if neither of you stops? \n" ); document.write( "
Algebra.Com's Answer #173723 by stanbon(75887)\"\" \"About 
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you can ride a bicycle 15 mph. your sister rides 12 mph. you give her a one hour head start. in how many hours will you catch up if neither of you stops?
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\n" ); document.write( "Your DATA:
\n" ); document.write( "rate = 15 mph ; distance = x miles ; time = d/r = x/15 hrs.
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\n" ); document.write( "Sister's DATA:
\n" ); document.write( "rate = 12 mph ; distance = x miles ; time = d/r = x/12
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\n" ); document.write( "Equation:
\n" ); document.write( "her time - your time = 1 hr
\n" ); document.write( "x/12 - x/15 = 1
\n" ); document.write( "Multiply thru by 60 to get:
\n" ); document.write( "5x - 4x = 60
\n" ); document.write( "x = 60 miles
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\n" ); document.write( "Your time to catch up: x/15 = 60/15 = 4 hrs
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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