document.write( "Question 235950: you can ride a bicycle 15 mph. your sister rides 12 mph. you give her a one hour head start. in how many hours will you catch up if neither of you stops? \n" ); document.write( "
Algebra.Com's Answer #173723 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! you can ride a bicycle 15 mph. your sister rides 12 mph. you give her a one hour head start. in how many hours will you catch up if neither of you stops? \n" ); document.write( "-------------- \n" ); document.write( "Your DATA: \n" ); document.write( "rate = 15 mph ; distance = x miles ; time = d/r = x/15 hrs. \n" ); document.write( "------------------------- \n" ); document.write( "Sister's DATA: \n" ); document.write( "rate = 12 mph ; distance = x miles ; time = d/r = x/12 \n" ); document.write( "-------------------------- \n" ); document.write( "Equation: \n" ); document.write( "her time - your time = 1 hr \n" ); document.write( "x/12 - x/15 = 1 \n" ); document.write( "Multiply thru by 60 to get: \n" ); document.write( "5x - 4x = 60 \n" ); document.write( "x = 60 miles \n" ); document.write( "---------------------------- \n" ); document.write( "Your time to catch up: x/15 = 60/15 = 4 hrs \n" ); document.write( "---------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |