document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=235916>Question 235916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello my name is anthony  and who ever reponds back to this it would be great cuz i am have trouble with algerbra equations with varibles on each sides and so i am new at this and so if you could tell me the steps and explain to me the best way you can that would be great\r<BR>\n" );
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document.write( "5x-3-=3x+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #173690 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=173690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x-3=3x+7<BR>\n" );
document.write( "subtract 3x from both sides<BR>\n" );
document.write( "5x-3x-3=3x-3x+7<BR>\n" );
document.write( "2x-3=7<BR>\n" );
document.write( "add 3 to both sides<BR>\n" );
document.write( "2x-3+3=7+3<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x=5 </SPAN>\n" );
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