document.write( "Question 235438: Is there a trick to finding the answer to (m-3)^5? (m-3) to the fifth power
\n" ); document.write( "thank you,
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Algebra.Com's Answer #173598 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
A handy thing to use is Pascals triangle
\n" ); document.write( "It looks like\r
\n" ); document.write( "\n" ); document.write( "1
\n" ); document.write( "1 - 2 - 1
\n" ); document.write( "1 - 3 - 3 - 1
\n" ); document.write( "1 - 4 - 6 - 4 - 1
\n" ); document.write( "1 - 5 - 10 - 10 - 5 - 1\r
\n" ); document.write( "\n" ); document.write( "The last line is the coefficients of the 6 terms of
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\n" ); document.write( "For your problem say
\n" ); document.write( "\"m+=+a\"
\n" ); document.write( "\"-3+=+b\"
\n" ); document.write( "Just keep following the pattern of Pascals triangle
\n" ); document.write( "for higher powers
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