document.write( "Question 30629: Solve the inequality: 5<1-3x (less than or equall to) 10 \n" ); document.write( "
Algebra.Com's Answer #17358 by sdmmadam@yahoo.com(530)\"\" \"About 
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Solve the inequality: 5<1-3x (less than or equall to) 10
\n" ); document.write( "5 < 1-3x < = 10 ----(1)\r
\n" ); document.write( "\n" ); document.write( "Consider 5 < 1-3x
\n" ); document.write( "5 - 1 <-3x
\n" ); document.write( "4 < -3x
\n" ); document.write( "That is -3x > 4
\n" ); document.write( "Dividing by (-3) and since division by a negative quantity alters the inequality, the greater than becoms less than
\n" ); document.write( "x < (-4)/3 ----(*)\r
\n" ); document.write( "\n" ); document.write( "Consider (1-3x) < = 10
\n" ); document.write( "1 - 10 <= 3x
\n" ); document.write( "-9 <= 3x
\n" ); document.write( "dividing by 3(>0) and since division by a positive quantity does not alter the inequality the less than remains less than
\n" ); document.write( "-3 <= x ----(**)\r
\n" ); document.write( "\n" ); document.write( "From (**) and (*), we conclude that
\n" ); document.write( "-3 <= x < (-4)/3 \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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